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Quelle que soit la fonction derivable
sur [0: 1]. 0n pose I(f) = 1∫-1 f(x)dx .
Alors pour toute foncti on f derivable sur [-1;2]. on a:
0∫1-f(x) dx = I(f)
1∫0 |f(x)| dx = |I(f)|
𝑏∫𝑎 ]2 – f(x)] dx = -2 + I(f)
1∫0 [f(x)]2 dx = (i(f))2